…을 가장한, 옛날에 AoPS에 답변으로 올렸지만 티스토리로 퍼오기 매우 귀찮아서 그냥 방치했던 계산 하나를 올려봅니다. 다른 꼴의 삼각함수 적분에도 쓸 수 있는 테크닉이 아닐까 해서 이렇게 올려봅니다.
Today's integral we are going to evaluate is a famous one,
.
Solution 1 (by elementary calculus). It is clear that
. To determine
for
, we consider the difference
for
. Some trigonometric identities show that

Since

it follows that
and
for
. Therefore
for all
.
Solution 2 (by complex analysis). It is easy to see, by the substitution
, that
.
Thus for
,

Since

we have
for
.
Solution 3 (by advanced calculus). Let
for
. We further assume
, for the convenience of calculation. Then

But note that

where
is the harmonic number, and logarithmic differentiation of

gives

which implies that

as
. Also, for
, we find that

Therefore we have

which simplifies to

In special cases, taking
for
gives
.
Today's integral we are going to evaluate is a famous one,
Solution 1 (by elementary calculus). It is clear that
Since
it follows that
Solution 2 (by complex analysis). It is easy to see, by the substitution
Thus for
Since
we have
Solution 3 (by advanced calculus). Let
But note that
where
gives
which implies that
as
Therefore we have
which simplifies to
In special cases, taking




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그보다 이 문제를 어떻게 구하냐와 구한 문제를 어떻게 이렇게 손쉽게 풀 수 있는지 궁금함 [앞으로 자주 들릴듯 하네요]
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