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A simple integral related to the zeta function

sos440 2013. 5. 16. 23:41

Residue 계산하면 금방 나오는 쉬운 계산입니다.

 

Proposition 1. We have

0x3(x4+1)(e2πx1)dx=γ2+π4sinπ2coshπ2cosπ218ω4=1Hω,

where Hs=γ+ψ0(1+s) is the analytic extension of the harmonic number.